Puzzles Test
Logical Reasoning Questions based on Puzzles Test can be tried upon in this question and answers. Attempt all of them to know if you understand it's basic concept.This section is very useful for those who are preparing for competitive exams such as Written test of Bank Exams, CAT Exams, Railway Exams, SSC, UPSC,Banking,Insurance, Defence and many more.

Q36.
Directions: Answer the question based on the following information:
In a “Fitness & Figure” gymnasium class, there are 15 females enrolled in Weight Loss program. They all have been grouped in any one of the 5 weightgroups W1, W2, W3, W4 or W5. One trainer is assigned to one group only. Anjali, Aarti, Archana and Shruti belong to the same group. Anjali and Rupa are in one group, Rupali and Renuka are also in one group. Rupa, Pinki, Renuka, Ruchika and Ritu belong to different group. Somya cannot be with Ritu and Tara cannot be with Pinki. Komal cannot be with Pinki, Somya or Ritu. Shruti is in W1 and Somya in W4 with Ruchika. Shweta and Jyotika cannot be with Rupali, but are in a weightgroup with total membership of four. No group can have can have more than five or less than one member. Amita, Babita, Chandrika, Deepika and Katrina are trainers of group with membership sizes 5, 4, 3, 2 and 1, respectively.
Who is the trainer of Pinki?Show Solution Report ErrorPlease Login here to view detailed solution of this question
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Q37.
Directions: Answer the question based on the following information:
In a “Fitness & Figure” gymnasium class, there are 15 females enrolled in Weight Loss program. They all have been grouped in any one of the 5 weightgroups W1, W2, W3, W4 or W5. One trainer is assigned to one group only. Anjali, Aarti, Archana and Shruti belong to the same group. Anjali and Rupa are in one group, Rupali and Renuka are also in one group. Rupa, Pinki, Renuka, Ruchika and Ritu belong to different group. Somya cannot be with Ritu and Tara cannot be with Pinki. Komal cannot be with Pinki, Somya or Ritu. Shruti is in W1 and Somya in W4 with Ruchika. Shweta and Jyotika cannot be with Rupali, but are in a weightgroup with total membership of four. No group can have can have more than five or less than one member. Amita, Babita, Chandrika, Deepika and Katrina are trainers of group with membership sizes 5, 4, 3, 2 and 1, respectively.
Deepika is the trainer of:Show Solution Report ErrorPlease Login here to view detailed solution of this question
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Q38.
Directions: Answer the question based on the following information:
In a “Fitness & Figure” gymnasium class, there are 15 females enrolled in Weight Loss program. They all have been grouped in any one of the 5 weightgroups W1, W2, W3, W4 or W5. One trainer is assigned to one group only. Anjali, Aarti, Archana and Shruti belong to the same group. Anjali and Rupa are in one group, Rupali and Renuka are also in one group. Rupa, Pinki, Renuka, Ruchika and Ritu belong to different group. Somya cannot be with Ritu and Tara cannot be with Pinki. Komal cannot be with Pinki, Somya or Ritu. Shruti is in W1 and Somya in W4 with Ruchika. Shweta and Jyotika cannot be with Rupali, but are in a weightgroup with total membership of four. No group can have can have more than five or less than one member. Amita, Babita, Chandrika, Deepika and Katrina are trainers of group with membership sizes 5, 4, 3, 2 and 1, respectively.
Which of the following are in one group?Show Solution Report ErrorPlease Login here to view detailed solution of this question
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Q39.
Directions: Answer the question based on the following information:
In a “Fitness & Figure” gymnasium class, there are 15 females enrolled in Weight Loss program. They all have been grouped in any one of the 5 weightgroups W1, W2, W3, W4 or W5. One trainer is assigned to one group only. Anjali, Aarti, Archana and Shruti belong to the same group. Anjali and Rupa are in one group, Rupali and Renuka are also in one group. Rupa, Pinki, Renuka, Ruchika and Ritu belong to different group. Somya cannot be with Ritu and Tara cannot be with Pinki. Komal cannot be with Pinki, Somya or Ritu. Shruti is in W1 and Somya in W4 with Ruchika. Shweta and Jyotika cannot be with Rupali, but are in a weightgroup with total membership of four. No group can have can have more than five or less than one member. Amita, Babita, Chandrika, Deepika and Katrina are trainers of group with membership sizes 5, 4, 3, 2 and 1, respectively.
Chandrika is the trainer of which weight group?Show Solution Report ErrorPlease Login here to view detailed solution of this question
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Q40.
Directions: Answer the question based on the following information.
Economists are assigned a number called Keynes number (named after the famous Economist, John Maynard Keynes). Only John Maynard Keynes himself has a Keynes number of zero. Any Economist who has written a research paper with Keynes has a Keynes number of 1. For other, Economists the calculation of his/her Keynes number is illustrated below
Suppose that an Economist, X has coauthored papers with several other Economists. From among them, Economists Y has the smallest Keynes number. Let the Keynes s number of Y be y. Then, X has a Keynes number of y + 1. Hence, any Economists with no coauthorship chain connected to Keynes have a Keynes number of infinity.
In a seven day long miniconference organized in memory of John Maynard Keynes, a close group of eight mathematicians, call them A, B, C, D, E, F, G and H, discussed some research problems. At the beginning of the conference, A was the only participant who had an infinite Keynes number. Nobody had a Keynes number less than that of F.
On the third day of the conference F coauthored a paper jointly with A and C. This reduced the average Keynes number of the group of eight mathematicians to 3. The Keynes number of B, D, E, G and H remained unchanged with the writing of this paper. Further, no other coauthorship among any three members would have reduced the average Keynes number of the group of eight to as low as 3.
At the end of the third day, five members of this group had identical Keynes number while the other three had Keynes numbers distinct from each other. On the fifth day, E coauthored a paper with F which reduced the group's average Keynes number by 0.5. The Keynes numbers of remaining six were unchanged with the writing of this paper. No other paper was written during the conference.
The Keynes number of C at the end of the conference wasShow Solution Report ErrorPlease Login here to view detailed solution of this question
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Q41.
Directions: Answer the question based on the following information.
Economists are assigned a number called Keynes number (named after the famous Economist, John Maynard Keynes). Only John Maynard Keynes himself has a Keynes number of zero. Any Economist who has written a research paper with Keynes has a Keynes number of 1. For other, Economists the calculation of his/her Keynes number is illustrated below
Suppose that an Economist, X has coauthored papers with several other Economists. From among them, Economists Y has the smallest Keynes number. Let the Keynes s number of Y be y. Then, X has a Keynes number of y + 1. Hence, any Economists with no coauthorship chain connected to Keynes have a Keynes number of infinity.
In a seven day long miniconference organized in memory of John Maynard Keynes, a close group of eight mathematicians, call them A, B, C, D, E, F, G and H, discussed some research problems. At the beginning of the conference, A was the only participant who had an infinite Keynes number. Nobody had a Keynes number less than that of F.
On the third day of the conference F coauthored a paper jointly with A and C. This reduced the average Keynes number of the group of eight mathematicians to 3. The Keynes number of B, D, E, G and H remained unchanged with the writing of this paper. Further, no other coauthorship among any three members would have reduced the average Keynes number of the group of eight to as low as 3.
At the end of the third day, five members of this group had identical Keynes number while the other three had Keynes numbers distinct from each other. On the fifth day, E coauthored a paper with F which reduced the group's average Keynes number by 0.5. The Keynes numbers of remaining six were unchanged with the writing of this paper. No other paper was written during the conference.
How many participants had the same Keynes number at the beginning of the conference?Show Solution Report ErrorPlease Login here to view detailed solution of this question
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Q42.
Directions: Answer the question based on the following information.
Economists are assigned a number called Keynes number (named after the famous Economist, John Maynard Keynes). Only John Maynard Keynes himself has a Keynes number of zero. Any Economist who has written a research paper with Keynes has a Keynes number of 1. For other, Economists the calculation of his/her Keynes number is illustrated below
Suppose that an Economist, X has coauthored papers with several other Economists. From among them, Economists Y has the smallest Keynes number. Let the Keynes s number of Y be y. Then, X has a Keynes number of y + 1. Hence, any Economists with no coauthorship chain connected to Keynes have a Keynes number of infinity.
In a seven day long miniconference organized in memory of John Maynard Keynes, a close group of eight mathematicians, call them A, B, C, D, E, F, G and H, discussed some research problems. At the beginning of the conference, A was the only participant who had an infinite Keynes number. Nobody had a Keynes number less than that of F.
On the third day of the conference F coauthored a paper jointly with A and C. This reduced the average Keynes number of the group of eight mathematicians to 3. The Keynes number of B, D, E, G and H remained unchanged with the writing of this paper. Further, no other coauthorship among any three members would have reduced the average Keynes number of the group of eight to as low as 3.
At the end of the third day, five members of this group had identical Keynes number while the other three had Keynes numbers distinct from each other. On the fifth day, E coauthored a paper with F which reduced the group's average Keynes number by 0.5. The Keynes numbers of remaining six were unchanged with the writing of this paper. No other paper was written during the conference.
The Keynes number of E at the beginning of the conference wasShow Solution Report ErrorPlease Login here to view detailed solution of this question
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