Triangles
Subject matter experts of JagranJosh have developed a chapter wise practice sets as per the relevancy of the chapter in the board exam. This practice set contains 10 questions with detailed explanations on “Chapter: Triangles” of Mathematics.

Q1.In the following fig. $$XY\text{}\left\right\text{}QR\text{}and\text{}\frac{PX}{XQ}=\frac{PY}{YR}=\frac{1}{2},\text{}then$$
Show Solution Report ErrorPlease Login here to view detailed solution of this question
Please Login here to report us any error for this question
Please wait... 
Q2.In the following figure QA AB and PB Ab, then AQ is:
Show Solution Report ErrorPlease Login here to view detailed solution of this question
Please Login here to report us any error for this question
Please wait... 
Q3.The ratio of the areas of two similar triangles is equal to the:
Show Solution Report ErrorPlease Login here to view detailed solution of this question
Please Login here to report us any error for this question
Please wait... 
Q4.The areas of two similar triangles are $$144\text{}c{m}^{2}and\text{}81\text{}c{m}^{2}$$. If one median of the first triangle is 16 cm, length of corresponding median of the second triangle is:
Show Solution Report ErrorPlease Login here to view detailed solution of this question
Please Login here to report us any error for this question
Please wait... 
Q5.Given Quad. ABCD Quad. PQRS then x is:
Show Solution Report ErrorPlease Login here to view detailed solution of this question
Please Login here to report us any error for this question
Please wait... 
Q6.If $$\Delta ABC\sim \Delta DEF,\text{}ar\left(\Delta DEF\right)\text{}=\text{}100\text{}c{m}^{2}and\text{}AB/DE\text{}=\text{}\frac{1}{2}\text{}then\text{}ar\left(\Delta ABC\right)\text{}$$ is:
Show Solution Report ErrorPlease Login here to view detailed solution of this question
Please Login here to report us any error for this question
Please wait... 
Q7.If the three sides of a triangle are a, $$\sqrt{3a},\sqrt{2a}$$, then the measure of the angle opposite to the longest side is:
Show Solution Report ErrorPlease Login here to view detailed solution of this question
Please Login here to report us any error for this question
Please wait...